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2w^2-5w=-3(2w+1)
We move all terms to the left:
2w^2-5w-(-3(2w+1))=0
We calculate terms in parentheses: -(-3(2w+1)), so:We get rid of parentheses
-3(2w+1)
We multiply parentheses
-6w-3
Back to the equation:
-(-6w-3)
2w^2-5w+6w+3=0
We add all the numbers together, and all the variables
2w^2+w+3=0
a = 2; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·2·3
Δ = -23
Delta is less than zero, so there is no solution for the equation
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